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Probability
A,B and C are among 15 speakers in the mobile world conference .what is the probability that A speaks before B and B speaks before C.
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P(A)=1/15
P(B/A)=1/14
P(C/B)=1/13
P(B/A)*P(C/B)=(1/14)*(1/13)=1/182 - 8 years agoHelpfull: Yes(1) No(0)
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