the area of a triangle whose vertices are A(3,2) B(11,8) and C(8,12) is

• property : we can shift the coordinates
  so making A as (0,0) then we have to subtract 3,2 from each
  new coordinates
  A(0,0), B(8,6), C(5,10)
  
  now applying, area = 0.5 * (x1*y2 - x2*y1)
  = 0.5*(8*10-6*5)
  = 0.5*50
  = 25
  area = 25 square units.
• 10 years agoHelpfull: Yes(1) No(0)
• area of triangle with 3 vertices is |[ax(by-cy)+bx(cy-ay)+cx(ay-by)]/2|
  where ax,ay;bx,by;cx,cy are the x and y coordinates of the given vertices.
  ans 22.5
  
• 10 years agoHelpfull: Yes(0) No(0)