Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

A. 9 B. 11
C. 13 D. 15

• Let numbers are n,n+2,n+4
  now 3n=2(n+4)+3
  3n-2n=11
  so
  n=11 then consecutive odd numbers are 11,13,15
• 11 years agoHelpfull: Yes(10) No(7)
• ANS. D
  
  from the given answers the possible three consecutive odd integers to consider to satisfy the condition are
  1) 5, 7, 9
  2) 7, 9, 11
  3) 9, 11, 13
  4) 11, 13, 15
  
  Only the option 4 satisfies Three times the first odd integers is 3 more than twice the third.
  Hence the third integer is 15
• 12 years agoHelpfull: Yes(7) No(5)
• ans 9
  2x+1, 2x+3, 2x+5 are the tree nos.
  3* 2x+1 + 3= 2 * 2x+5
  x=2
  ans 9
• 10 years agoHelpfull: Yes(6) No(3)
• Answer: Option D
  
  Explanation:
  
  Let the three integers be x, x + 2 and x + 4.
  
  Then, 3x = 2(x + 4) + 3 x = 11.
  
  Third integer = x + 4 = 15.
• 8 years agoHelpfull: Yes(3) No(1)
• Three integers x,x+2,x+4
  3x=3+2(x+4)
  3x=3+2x+8
  x=11
  Therefore 3rd integer is: x+4=11+4=15
• 7 years agoHelpfull: Yes(3) No(0)
• Three consecutive odd numbers
  2x+1,2x+3,2x+5
  
  3(2x+1) = 2(2x+5) + 3
  Slove this,
  X=5
  Third num is 2(5)+5=15
• 5 years agoHelpfull: Yes(1) No(0)
• let numbers are x+1,x+3,x+5
  3(x+1)=3+2(X+5)
  X=10
  SO,
  11,13,15 are the numbers.
• 5 years agoHelpfull: Yes(0) No(0)