TCS
Company
Numerical Ability
Permutation and Combination
(3^34)/55 find out the reminder
N.B.- Here euler fails
Read Solution (Total 13)
-
- ans is 4
cyclicity of 3 is 4
s0 divide 34 by 4, u get 2 as remainder
now 3^2 is 9
divide 9 by 5
remainder is 4 - 10 years agoHelpfull: Yes(19) No(13)
- According to remainder thereom
(3^34)/55=(((3^4)^8)*3^2)/55
={((26)^8)*9}/55
=(31*9)/55
i.e.,remainder=4 - 10 years agoHelpfull: Yes(14) No(5)
- @ RITESH KUMAR and SARABESHWAR
According to remainder thereom
(3^34)/55=(((3^4)^8)*3^2)/55
={((26)^8)*9}/55
={[(26^2)^4]*9}/5
={[(16^4)*9]}/55
=[(36^2)*9]/55
=[(-19^2)*9]
=(361*9)/55
=[{(55*6)+31}*9]/55
=(31*9)/55
i.e.,remainder=4
- 10 years agoHelpfull: Yes(9) No(5)
- Ans is 4
(a*b*c)%x=a%x*b%x*c/x.
(3^34)%55=(3^10%55)*(3^10%55)*(3^10%55)*(3^4%55)
3^10%55=(3^4%55)*(3^4%55)*3^2%55
so 3^10%55=26*26*9%55=34
so then
3^34=34*34*34*26=4 - 10 years agoHelpfull: Yes(7) No(1)
- Kv Chowdary friend how come you got 31 plzzz explain
- 10 years agoHelpfull: Yes(1) No(1)
- first -55=5*11
then apply euler - 10 years agoHelpfull: Yes(1) No(0)
- (3^34)/55 can also be written as (9^17)/55
now apply binomials theorem and the result will become 169/55 whose remainder is 4 - 10 years agoHelpfull: Yes(1) No(0)
- (3^34)/55=(((3^4)^8)*3^2)/55
={((26)^8)*9}/55
={[(26^2)^4]*9}/5
={[(16^4)*9]}/55
=[(36^2)*9]/55
=(31*9)/55
=279/55
=4 - 10 years agoHelpfull: Yes(1) No(0)
- any no. can be written in form 4n+1 ...3^34 =3^(32+2)=3^2=9
9/55 remainder = 9 - 10 years agoHelpfull: Yes(0) No(0)
- Remainder is 4
- 10 years agoHelpfull: Yes(0) No(1)
- 3^34/55=3^2/(5^1*11^1)=9/5=4
for finding reminder of a number
for base we have to take the unit digit and for power we have to divide with 4
ex:31^22=(1)^2=1 is unit digit - 10 years agoHelpfull: Yes(0) No(0)
- @ KV CHOWDARY 3^4 that becames 26.....how
- 10 years agoHelpfull: Yes(0) No(0)
- According to remainder thereom
(3^34)/55=(((3^4)^8)*3^2)/55
={((26)^8)*9}/55
={[(26^2)^4]*9}/5
={[(16^4)*9]}/55
=[(36^2)*9]/55
=[(-19^2)*9]
=(361*9)/55
=[{(55*6)+31}*9]/55
=(31*9)/55
i.e.,remainder=4 - 10 years agoHelpfull: Yes(0) No(2)
TCS Other Question