The identical circles intersect their centres,and the points at which they intersect,form a square of side 1 cm .the area in sq.cm of portion that is common to the two circles is :

a. sqrt 5
b. 4
c. pie/2-1
d. sqrt2-1

• two identical circles are intersects at center, and form a square so radious =1 cm.
  area of arc ay 90*= (90/360)pi**1*1=pi/4
  and area of triangle=1/2*1*1
  so area of common part= 2*[(pi/4)-1/2]= pi/2-1 ans....
• 9 years agoHelpfull: Yes(12) No(0)
• Area of sector -Area of Square
  assume area of one sector as a semi-cirlce for which diagonal of a square is the diameter diagonal= sqrt(2)
  half of the diagonal=1/root2= radius of semicirlce
  area of semicirlcle= 1/2(pi*1/root2*1/root2);
  for another sector also same so, total area of sector=pi/2;
  and
  area of square=1*1=1
  so,ans is pi/2-1;
• 9 years agoHelpfull: Yes(3) No(0)
• ANS:3)pie/2-1
• 9 years agoHelpfull: Yes(2) No(1)