Divide 50 into two parts so that sum of the reciprocal is 1/12 ?

• 1/x + 1/(50-x)=1/12
  x^2-50x+600=0
  x=20,30
  then the no.s are 20,30 :)
• 10 years agoHelpfull: Yes(15) No(0)
• let two no be x,y
  x+y=50 ....eq(1)
  1/x+1/y=1/12...eq(2)
  x+y/xy=1/12(using eq(1))
  xy=600
  now, (x-y)^2=(x+y)^2 -4xy
  using above
  x-y=10.....eq(3)
  solving eq(1) & eq(2)
  x=30 & y=20
• 10 years agoHelpfull: Yes(7) No(0)
• let one number be x
  the other number will be 50-x
  1/x + 1/(50-x)= 1/12
  50-x+x = x(50-x)/12
  600 = 50x-x^2
  x^2-50x+600=0
  x^2-30x-20x+600=0
  x(x-30)-20(x-30)=0
  (x-30)(x-20)=0
  x= 20 or 30
  the numbers are 20 and 30
• 10 years agoHelpfull: Yes(3) No(0)
• 20,30
  1/50 + 1/(50-x)= 1/12
  on solving the equation we get ans 20,30
• 10 years agoHelpfull: Yes(3) No(0)
• let first part is x
  second paret is 50-x
  so 1/x+1/(50x)=1/12
  sove it got 20,30
• 10 years agoHelpfull: Yes(2) No(0)
• let 1st no=x
  so,2nd will b 50-x
  now,
  A.T.Q
  1/x + 1/50-x = 1/12
  solving we get x=20 or x=30
  
  so,ans is (20,30)
• 10 years agoHelpfull: Yes(1) No(0)
• 30 & 20
  1/x + 1/(50-x)=1/12
  x^2-50x+600=0
  x=20,30
  
• 10 years agoHelpfull: Yes(1) No(0)
• 1/x+1/50-x=1/12
  x^2-50x+600=0
  x=20,30
  
• 10 years agoHelpfull: Yes(0) No(0)
• 1/a + 1/b =1/12
  a+b=50
  solving we get a*b=50*12
  a-b =sqrt[(a+b)^2-4*a*b]= 10
  solving a+b,a-b we get
  a=30 b=10
• 10 years agoHelpfull: Yes(0) No(1)
• x+y=50
  1/x+1/Y=1/12
  
  by solving these two eqn we get 20,30
• 10 years agoHelpfull: Yes(0) No(0)
• 30,20
  1/30+1/20=1/12
  
• 10 years agoHelpfull: Yes(0) No(0)
• 20 and 30 ......
  explanation: 1/20+1/30=1/12
• 10 years agoHelpfull: Yes(0) No(0)
• (1/x)+(1/50-x)=(1/12)
  by solving
  x=20,30.
  
• 10 years agoHelpfull: Yes(0) No(0)
• 30+20=50
  1/30+1/20=1
  /12
• 10 years agoHelpfull: Yes(0) No(0)