if n be a positive even integer,then the last two digits of the number (8)^2n-(6)^2n

• last two digits are zero
  take n=2
  8^4-6^4= (8^2)^2-(6^2)^2=(64-36)(64+36)=2800
  last two digits are 00
• 9 years agoHelpfull: Yes(2) No(0)
• ans is 00
  last two digits will be zero
• 9 years agoHelpfull: Yes(1) No(0)