A number consists of 3 digits whose sum is 10. The middle digit is equal to the sum of the other two and the number will be increased by 99 if its digits are reversed. The number is:

A. 145 B. 253
C. 370 D. 352

• Go Through options
  ans will be 253..
  which on reversing gives 352
  (253+99).
• 12 years agoHelpfull: Yes(14) No(3)
• let the digits of the No. be x. y & z
  Hence, x+y+z=10.................(1)
  x+z=y..............(2)
  AS per the condition
  (100x+10y+z)-(100z+10y+x)=99
  Solving ,the value of (x-z)=1
  From equation (1) and (2)
  2y=10, y=5
  Hence, the option D satisifies all the conditions
• 13 years agoHelpfull: Yes(2) No(6)
• we can easily solve the ans using the result
  all options are fullfill 1st condition ie the sum of digit is 10
  now only B and D are full fill the 2nd condition ie middle digit = sum of the side digit
  now finally B is the result bcze if we add two number the number must be increase but here if we reverse 352 then it become 253 but if we add 99 the itnever be a small number so thats why result is 253
  B
• 8 years agoHelpfull: Yes(1) No(0)
• its very easy.....check by option
  
• 9 years agoHelpfull: Yes(0) No(1)
• by looking at options u can solve
• 7 years agoHelpfull: Yes(0) No(1)