A man can row 30 km upstream and 44 km downstream in 10 hours. Also, he can row 40 km upstream and 55 km downstream in 13 hours. Find the rate of current and the speed of the man in still water.

• Let rate upstream = x km / hr and rate downstream = y km / hr.
  Then, 40x+ 55y =13 ...(i)
  and 30x+44y=10 ...(ii)
  Multiplying (ii) by 4 and (i) by 3 and
  subtracting, we get y=11.
  Substituting y = 11 in (j), we get : x =
  5.
  Rate in still water =12(11+5)kmph=8kmph.
  Rate of current= 12(11−5) kmph=3kmph.
• 10 years agoHelpfull: Yes(0) No(0)
• Let rate upstream = x km / hr and rate downstream = y km / hr.
  Then, 40x+ 55y =13 ...(i)
  and 30x+44y=10 ...(ii)
  Multiplying (ii) by 4 and (i) by 3 and
  subtracting, we get y=11.
  Substituting y = 11 in (j), we get : x =
  5.
  Rate in still water =12(11+5)kmph=8kmph.
  Rate of current= 12(11−5) kmph=3kmph.
• 10 years agoHelpfull: Yes(0) No(0)
• Let rate upstream = x km / hr and rate downstream = y km / hr.
  Then, 40x+ 55y =13 ...(i)
  and 30x+44y=10 ...(ii)
  Multiplying (ii) by 4 and (i) by 3 and
  subtracting, we get y=11.
  Substituting y = 11 in (j), we get : x =
  5.
  Rate in still water =12(11+5)kmph=8kmph.
  Rate of current= 12(11−5) kmph=3kmph.
• 10 years agoHelpfull: Yes(0) No(0)
• Let rate upstream = x km / hr and rate downstream = y km / hr.
  40x+ 55y =13 ...(i)
  30x+44y=10 ...(ii)
  subtracting, we get y=11.
  Substituting y = 11 in (j), we get : x =5.
  Rate in still water =12(11+5)kmph=8kmph.
  Rate of current= 12(11−5) kmph=3kmph.
• 10 years agoHelpfull: Yes(0) No(0)
• Let rate upstream = x km / hr and rate downstream = y km / hr.
  40x+ 55y =13 ...(i)
  30x+44y=10 ...(ii)
  subtracting, we get y=11.
  Substituting y = 11 in (j), we get : x =5.
  Rate in still water =12(11+5)kmph=8kmph.
  Rate of current= 12(11−5) kmph=3kmph.
• 10 years agoHelpfull: Yes(0) No(0)
• Let rate upstream = x km / hr and rate downstream = y km / hr.
  40x+ 55y =13 ...(i)
  30x+44y=10 ...(ii)
  subtracting, we get y=11.
  Substituting y = 11 in (j), we get : x =5.
  Rate in still water =12(11+5)kmph=8kmph.
  Rate of current= 12(11−5) kmph=3kmph.
• 10 years agoHelpfull: Yes(0) No(0)