anup manages to draw 7 circles of equal radii with their centres on the diagonal of a square such that two extreme circles touch two sides of the square and each middle circle touches two circles on either side. find the ratio of radius of the circles to the side of the square.
a. 1:(2+6^(1/2))
b. 1:(4+7^(1/3))
c. (2+7^(1/2)):1

• diagonal of square=(2*r)*7+(2^(1/2)*r-r)*2
  diagonal has 7 squares diameters length +little distance between extreme squares to the end point [form a square of side r from center of extreme circle to the extreme end to find distance]
  distance=2^(1/2)*r-r
  D=a*2^(1/2)
  a=2^(1/2)*[6*r + 2^(1/2)*r]
  
  r/a =1:[2+6*2^(1/2)]
  answer is none of the above
• 9 years agoHelpfull: Yes(13) No(9)
• let the side of the square be a cm...
  
  so the length of the diagonal will be sqrt(2)a (2^1/2 *a)
  
  if the radius of the circle is r then
  
  7*2r = sqrt(2)a
  r = a/7sqrt(2)
  
  r:a = 1:7sqrt(2) ....
• 9 years agoHelpfull: Yes(1) No(2)
• ans is a.1:(2+6^(1/2))
  
• 9 years agoHelpfull: Yes(1) No(4)