void fn int main int n 3 fn n void fn int n if n 0 fn --n printf d

does not print anything ans function is called recursively 3210.when n becomes 0 if statement wont get executed
9 years agoHelpfull: Yes(8) No(3)
it doesnt produce output, because fn calls itself. if n becomes 0 then if condition is not true.
9 years agoHelpfull: Yes(1) No(2)
2
0
is the output
8 years agoHelpfull: Yes(1) No(0)
f(3) -> f(2) -> f(1) ->f(0)
print 0 f(-1)
print 1
9 years agoHelpfull: Yes(0) No(1)
ans is :0102010
8 years agoHelpfull: Yes(0) No(0)

void fn(int);
main()
{
int n=3;
fn(n);
}
void fn(int n)
{
if(n>0)
{
fn(--n);
printf("%d",n);
fn(--n);
}
}