find the sum of 100, in the series, 1+2+3+....n, given first series 1+2+3+4, find the other series

• (1+2+3+4+...n)=n(n+1)/2
  here n=100
  so,sum=100*101/2=50*101=5050
  
  1+2+3+4=10
  
  ans=5050-10=5040
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• May be Ans : 2540
  sigma(100)= 100(100+1)/2
  =50*51
  =2550
  first series is 1+2+3+4 = 10
  Remaning series is is 2550-10 = 2540
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