The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

A. 9 cm B. 18 cm
C. 20 cm D. 41 cm

• a^2+b^2=41^2
  a*b=20
  (a+b)^2=41^2+2*20
  =1681+40
  =1721
  a+b=under root of 1721
  2 (a+b)=2*under root of 1721
• 10 years agoHelpfull: Yes(2) No(0)
• D.41
  
  a^2+b^2=41^2
  a*b=20
  (a+b)^2=a^2+b^2+2a*b
  a+b=41.
• 12 years agoHelpfull: Yes(1) No(4)
• 41^2=40^2+9^2 so length=40,breadth=9 perimeter=2*(l+b)=2(40+9)=98
• 9 years agoHelpfull: Yes(0) No(0)
• OPTION B IS THE ANSWER
• 9 years agoHelpfull: Yes(0) No(0)
• 18 is correct answer
• 7 years agoHelpfull: Yes(0) No(0)