Solve the problem
(16937^30)/31

• n^p-1/p=1
  ans:n^(31-1)/31=1
• 9 years agoHelpfull: Yes(11) No(1)
• if question is of the form [(number)^(p-1)]/p where p is the prime no. then remainder is always 1.
• 9 years agoHelpfull: Yes(4) No(0)
• n^p-1/p=1
  ans:n^(31-1)/31=1
• 9 years agoHelpfull: Yes(1) No(0)
• take 16937(mod 31)
  remainder is 11
  
• 9 years agoHelpfull: Yes(0) No(3)
• Answer is 1
• 9 years agoHelpfull: Yes(0) No(0)
• (16937 ^30 )/30
  (p^31 -1)/31=1
  remainder =1
• 9 years agoHelpfull: Yes(0) No(0)
• 17 should be the answer
• 9 years agoHelpfull: Yes(0) No(1)