TCS
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Numerical Ability
Number System
Solve the problem
(16937^30)/31
Read Solution (Total 7)
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- n^p-1/p=1
ans:n^(31-1)/31=1 - 10 years agoHelpfull: Yes(11) No(1)
- if question is of the form [(number)^(p-1)]/p where p is the prime no. then remainder is always 1.
- 10 years agoHelpfull: Yes(4) No(0)
- n^p-1/p=1
ans:n^(31-1)/31=1 - 10 years agoHelpfull: Yes(1) No(0)
- take 16937(mod 31)
remainder is 11
- 10 years agoHelpfull: Yes(0) No(3)
- Answer is 1
- 10 years agoHelpfull: Yes(0) No(0)
- (16937 ^30 )/30
(p^31 -1)/31=1
remainder =1 - 10 years agoHelpfull: Yes(0) No(0)
- 17 should be the answer
- 10 years agoHelpfull: Yes(0) No(1)
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