How many 5s will be there in number 121122123124125...............til 356

• counting series is 121 122 123 124 125 126 .... till 356.
  
  from 121 to 200 => no. of times 5 appears=18
  201 to 300 => no. of times 5 appears=20
  301 to 356 => no. of times 5 appears=13
  
  total= 18+20+13= 51
• 10 years agoHelpfull: Yes(30) No(0)
• 121-200={125,135,145,150,151,152,153,154,155,156,157,158,159,165,175,185,195}=18
  200-300={205,215,225,235,245,250,251,252,253,254,255,256,257,258,259,265,275,285,295}=20
  300-356{305,315,325,335,345,350,351,352,353,354,355,356}=13
  so ans is 18+20+13=51
  
• 10 years agoHelpfull: Yes(6) No(0)
• it should be 51
• 10 years agoHelpfull: Yes(3) No(0)
• for every 100 successive no. 5 appears 20 times.
  121-221= 20
  222-322=20
  325,35,45=3
  50-56=8(55 hv two 5s)
  20+20+3+8=51
• 10 years agoHelpfull: Yes(3) No(0)
• Till the end may be 23
• 10 years agoHelpfull: Yes(1) No(3)
• answer is 22 no of 5s if the follwing above no is written til 356 digits...
• 10 years agoHelpfull: Yes(0) No(4)
• 47 is the ans
• 10 years agoHelpfull: Yes(0) No(3)
• A - - - - =24 ways
  E - - - - =24 ways
  so, 49th = MAERS
• 10 years agoHelpfull: Yes(0) No(0)
• It is 18+20+13=51
• 10 years agoHelpfull: Yes(0) No(0)