If 378 coins consists of rupees, 50 paise and 25 paise coins, whose values are in the ratio 13 : 11 : 7, the number of 50 paise coins will be
(a) 132 (b) 128
(c) 136 (d) 133

• let the no. of 25 paise be - x
  50 - y
  1 rupee -z
  
  so we can write,
  (0.5*y)/(0.25*x) = 11/7
  => y = 11/14 x ......(i)
  
  again for 1 rupee and 25 paise
  (1.0 *z)/(0.25*x) = 13/7 ...(ii)
  =>z = 13/28
  total no. of coins
  x+y+z = 378
  x(1+(11/14)+(13/7))=378
  x=168
  
  so the number of 50 paise
  y = (11/14)*168 = 132
  
  so option a is the answer
  
• 10 years agoHelpfull: Yes(5) No(2)
• 132
  coz 50 paise are in the ratio of 11
  and 132 =11*12
  
• 10 years agoHelpfull: Yes(4) No(5)
• answer is A
  only 132 is divisible by 11
• 7 years agoHelpfull: Yes(0) No(4)