When four dice are thrown, what is the probability that the same number appears on each of them ?

• no of required events={(1111),(2222),(3333),(4444),(5555),(6666)}=6
  total event=6^4=1296
  probability=6/1296=1/216
• 10 years agoHelpfull: Yes(19) No(0)
• 1/6^3=1/216
  TOTAL NO.OF EVENTS=6^4=1296
  AND HAVING SAME NO.ON ALL FOUR ARE ONLY 6 CASES SO=6/6^4=1/6^3
• 10 years agoHelpfull: Yes(3) No(0)
• it will be 6/6^4 = 1/6^3
• 10 years agoHelpfull: Yes(2) No(0)
• same numer are (1,1,1,1),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)
  these are the favourable case
  total case 6*6*6*6
  hense p(A)=6/6*6*6*6=6/216
• 10 years agoHelpfull: Yes(1) No(3)
• Number of required events =6
  i.e (1111),(2222),(3333),(4444),(5555),(6666)
  total events = 6^4
  probability= 6/6^4 = 1/6^3 = 1/216
• 10 years agoHelpfull: Yes(1) No(0)
• (1/6)^4
  the probability for one no=1/6
• 10 years agoHelpfull: Yes(0) No(4)