If v w x y and z are non negative integers each less than 11 than how many distinct combination

Dividing 151001 by 11^4 give quotient 10 and remainder 4591

So

151001 = 10*11^4 + 4591

Dividing 4591 by 11^3 gives quotient 3 and remainder 598

So

151001 = 10*11^4 + 3*11^3 + 598

Dividing 598 by 11^2 gives quotient 4 and remainder 114

So

151001 = 10*11^4 + 3*11^3 + 4*11^2 + 114

Dividing 114 by 11 gives quotient 10 and remainder 4

So

151001 = 10*11^4 + 3*11^3 + 4*11^2 + 10*11 + 4

So v=10, w=3, x=4, y=10, z=4
10 years agoHelpfull: Yes(9) No(0)
only one combinatin satisfy
the value of v=10
w=3
x=4
y=10
z=4
which is in base 11 form.
10 years agoHelpfull: Yes(2) No(0)
bhai log maine elitmus ka exam 28 september ko diya tha kya hum phir se 5 oct.ko de sakte hai same id se ,or dono ka result declare hoga ya jo last me diye uska pls batao
10 years agoHelpfull: Yes(2) No(1)
Please explain how did you recognize Hari?
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@Ravi Bhardwaj
formula and v,w,x,y,z
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@Ravi Bhardwaj
formula and constraints v,w,x,y,z
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36 by basics algebra identities frst by subtacting 2 we can form it square and then soving
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If v,w,x,y and z are non negative integers, each less than 11, than how many distinct combination of (v,w,x,y,z) satisfy v(11^4) + w(11^3) + x(11^2) + y(11) + z=151001