There are 5 distinct integers a,b,c,d,e in ascending order.
(68-a)(68-b)(68-c)(68-d)(68-e)=725.
then what is the value of a+b+c+d?

• Sorry the previous approach was wrong
  725 = -5*-1*1*5*29
  so we can write,
  68-e = -5
  => e = 73
  68-d = -1
  => d = 69
  68-c = 1
  => c = 67
  68 - b = 5
  => b = 63
  68-a= 29
  => a = 39
  
  so a+b+c+d = 39+63+67+69 = 238
• 9 years agoHelpfull: Yes(9) No(3)
• previous answer is wrong
  
  725 = -58-1*1*5*29
  so we can write,
  68-e = -5
  => e = 73
  68-d = -1
  => d = 69
  68-c = 1
  => c = 67
  68 - b = 5
  => b = 63
  68-a= 29
  => a = 39
  
  so a+b+c+d = 39+63+67+69 = 238
  
  
• 9 years agoHelpfull: Yes(8) No(3)
• lcm of 725 = 5*5*29
  so we can also write 725 as a distinct multiples of numbers as
  725 = -5*-1*1*5*29
  so as a,b,c,d,e are in ascending order
  => a=-5, b=-1, c=1, d=5, e=29
  
  a+b+c+d = -5-1+1+5 = 0
  so the answer is 0
  
• 9 years agoHelpfull: Yes(4) No(15)
• 725=5*5*29 or 725=5*-5*-1*1*29
  therefore (68-63)*(68-73)*(68-67)*(68-69)*(68-69)
  a=63 b=73 c=67 d=69 e=39
  a+b+c+d+e=311
  311-63=248
  311-73=238
  311-67=244
  311-69=242
  311-39=272
  ans would be one among 248, 238, 244, 242, 272
• 9 years agoHelpfull: Yes(2) No(1)
• not possible
  
• 9 years agoHelpfull: Yes(1) No(2)
• 725 = -5*-1*1*5*29
  so we can write,
  68-a = -5
  => a = 73
  68-b = -1
  => b = 69
  68-c = 1
  => c = 67
  68 - d = 5
  => d = 63
  68-e= 29
  => e = 39
  
  so a+b+c+d = 73+69+67+63= 272
• 9 years agoHelpfull: Yes(1) No(4)
• 67+67+67+43=244
• 9 years agoHelpfull: Yes(0) No(3)
• 725=5*5*29=>
  now let us see the order:
  case1: 5*5*29*1*1:it is not possible because (ab=63
  68-c=1=>c=67
  68-d=-1=>d=69
  68-e=-5=>e=73
  (a
• 9 years agoHelpfull: Yes(0) No(2)