in how many ways seven letters between A & B be arranged from alphabets so that repetition is not allowed?

• 7 letters between A & B &,A,B has a fixed position
  so,
  24P7 * 2!
• 9 years agoHelpfull: Yes(30) No(4)
• TCS Ans 36*24!
  
• 9 years agoHelpfull: Yes(10) No(2)
• there should be seven letters in between i.e. 7 places to be occupied by the (26-2) alphabets , since A and B wont be repeated.
  Hence the ans will be 24P7
• 9 years agoHelpfull: Yes(9) No(7)
• 7 letters can be arranged in 24p7 ways
  and there will be 2! ways of arrangement of two words A&B,B&A
  and now consider the these 9 words as a single word therefore rest of the words can be arranged as (26-9+1)! ways
  ans:24p7*2!*18!
• 9 years agoHelpfull: Yes(8) No(0)
• 7 letters between a and b means a and b are fixed at first and last position.
  so remaining space 5, letters=5
  5!=120
• 9 years agoHelpfull: Yes(3) No(13)
• A 24*23*22*21*20 B = 5100480 there is remaining 24 letter so after permutation..
  
• 9 years agoHelpfull: Yes(2) No(2)
• There are 7 letters between A&B, we can choose 7 letters from remaining alphabet i.e(26-2). So 24p7, again we can change the positions of A& B hence solution is 2*24p7
• 9 years agoHelpfull: Yes(1) No(1)
• A _ _ _ _ _ _ _ B
  7 PLACES CAN BE FILLED IN BY 24 LETTERS
  24P7*2 AS A AND B CAN BE WRITTEN IN TWO WAYS
  
• 9 years agoHelpfull: Yes(1) No(3)
• 24p7*2!*7* bcoz a&b can change there position in two ways and those 7 alphabets can also change there position in 7 ways
• 9 years agoHelpfull: Yes(1) No(2)
• 24C7*2
  7 letters can be selected in 24C7 ways.
  and a&b can be placed in 2 ways
• 9 years agoHelpfull: Yes(1) No(1)
• 24 letters can be placed in 7 positions in 24p7 ways and a and b can interchange their places also so ans is 24p7*2!
• 9 years agoHelpfull: Yes(1) No(0)
• 24P7
  correct ans pls?
  
• 9 years agoHelpfull: Yes(0) No(3)
• there are 2 ways for A and B, and in between 7 letters without rep
  24*23*22*21*20*19*18* 2! for A and B
• 9 years agoHelpfull: Yes(0) No(3)
• in b/w a&b with out repetition 24p7 ways are possible..
  and b/w b&a also 24p7 ways are possible
  soo the ans is 24p7+24p7=24p7 * 2
• 9 years agoHelpfull: Yes(0) No(3)
• ans 26p7
  because we thave to arrange 7 letter out of 28 letter
  but there is A and B is already given and repetation is not possible so 28-2=26 .
  so 26p7
  
  
• 9 years agoHelpfull: Yes(0) No(7)
• 24p7*2*7! bec...... 7 out of 24 .theses 7 can arrange in 7! and 2 ways of arranging and b
  
• 9 years agoHelpfull: Yes(0) No(0)
• 36*24! ans is crct or not ? plss tell
  
• 9 years agoHelpfull: Yes(0) No(0)
• no of ways of distributing "n" distinct things to "r" different persons is r^n.
  since nobody can be excluded from getting a gift, we will subtract the possibility of getting 0 gifts ie 4 cases.
  so solution would be r^n-4
• 8 years agoHelpfull: Yes(0) No(0)