It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?

A. (216 + 1) B. (216 - 1)
C. (7 x 223) D. (296 + 1)

• Let 232 = x. Then, (232 + 1) = (x + 1).
  
  Let (x + 1) be completely divisible by the natural number N. Then,
  
  (296 + 1) = [(232)3] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N
• 11 years agoHelpfull: Yes(1) No(1)