in octagon the possible diagonals are

for any polygon
no of diagonal=n(n-3)/2,where n=no of sides
here n=8
so diagonals=8(8-5)/2
=20 ans
10 years agoHelpfull: Yes(17) No(6)
No. of diagonal in n sided polygon is n(n-3)/2.
since it is octagon
hence
8(8-3)/2
8*5/2=20
10 years agoHelpfull: Yes(6) No(0)
The formula is:nC2-n.
So,the answer is:8c2-8=20
10 years agoHelpfull: Yes(2) No(2)
answer is 20...because to find diagonal
formula is N*(n-3)/2

that is here n=8 because octagon

8*(8-3)/2 = 20
10 years agoHelpfull: Yes(1) No(0)

in octagon the possible diagonals are?