There are some students in the class teacher arranged them in a circle,number 40 is facing number 12 what is the maximum number of boys facing the girls.... 10 number of girls more than boys....?

• let there r x no of boys.
  So no of girls=x+10
  total=2x+10
  
  they r arranged in circle.
  40th student is facing 12.
  so consider a circle with 12 and 40 opposite to each other just like 12 &6 are opposite in a watch.
  therefore no of students in between 40 &12 =40-12-1=27
  (like 12-6-1=5 in watch)
  now count starts from 1
  so (12-1=11 students)+ (16 students)=27 students
  therefore last student=40+16=56th student.
  
  total=2x+10=56
  x=23
  
  no of boys=23
  no of girls=33
  maximum possible ways that boys may face girls should be 23 as boys no is less than girls.
• 10 years agoHelpfull: Yes(11) No(0)
• let no. of oys = x;
  girls == x+10;
  40 face 12
  so , no.of student between them is 40 - 12 = 28;
  so total no.of student(girls+boys)== 28*2==56;
  now;
  x(boys)+(x+10)(girls)==56;
  2x+10==56;
  2x==46;
  x==23;
  so maximum boys face girls is 23;
  an no.of girls==33;
• 10 years agoHelpfull: Yes(2) No(0)
• very clear solution ... thnx @Tania
• 10 years agoHelpfull: Yes(0) No(0)