There is a truck driver starts from one place to pick another person at
another place. The driver goes to that place by 6 AM and then picking him
he returns back.one day the other person woke a bit early and started
walking towards the first place.one the way he meets truck driver and joins
him and both went back to the first place. This day the other person came
20 min early to the time he usually comes to the first place?Tell the time
when the driver met the second person that day?

• 5.50AM
  20/2=10
  
• 10 years agoHelpfull: Yes(32) No(3)
• ans 5:50.
  since they reached 20 mins earlier therefore the driver must have saved the distance of 10 mins going and 10 mins coming back therefore he met the person 10 mins from the station so they met at 5:50
• 10 years agoHelpfull: Yes(13) No(0)
• Answer : 5.50 AM
  Given that the first person reaches the first place by 6.00 AM
  But,one day the second person reached the place 20 min early.
  and met the first person on the way ad reached the stop at 6.00 AM.
  Therfore,They would have met at 5.50 AM.
• 9 years agoHelpfull: Yes(2) No(0)
• pls explain clearly
• 10 years agoHelpfull: Yes(1) No(0)
• 5.40 am . 20 min early 6.00-20 min= 5.40 am
• 10 years agoHelpfull: Yes(0) No(19)
• wat is d correct answer...plzz sumone explain
• 10 years agoHelpfull: Yes(0) No(0)
• the correct answer is 5:50.since the drive takes 10 min to cover the distnce frm where the other person met and 10 mins coming back to that place as it saved his 20 mins.
• 10 years agoHelpfull: Yes(0) No(1)
• I think the data is not sufficient to conclude the time...
  As it has been told that first person goes towards second person at 6 but have not mentioned when he reaches to the second person or at the work place
• 10 years agoHelpfull: Yes(0) No(0)
• any one ps explain it clearly..
  
• 10 years agoHelpfull: Yes(0) No(0)