Elitmus
Exam
Logical Reasoning
ABCD is a rectangle , P & Q are the two points on AD & BC respectively.
x is another point on AB .
Now what is the ratio of ar(PQCD)/ar(xcd)...???
i) PD=QC
ii) AB= 4 * XB
Read Solution (Total 5)
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- Q is wrong...It is not a full q
actual ques...
ABCD is a rectangle , P & Q are the two points on AD & BC respectively.
x is another point on AB .
Now what is the ratio of ar(PQCD)/ar(xcd)...???
i) P is mid point on AD & Q is mid point on BC
ii) AB= 4 * XB
and ans is only (i) is required
- 10 years agoHelpfull: Yes(8) No(1)
- both statement is required to find this ratio because
1 statement only gives the area of pqcd not the area of xcd(for area of xcd,we have to find distance between x and a or b)
2 statement gives distance between x and a or b...hence both stst required - 10 years agoHelpfull: Yes(4) No(2)
- both statement are require
a statement clear area of pqcd i.e area of abcd/2
b statement also clear x position and gives
xd = root(ad^2 + xa^2)
xc = root(xb^2+bc^2)
s(semiperimeter of xcd) = (xd + xc + cd)/2
now we can calc area of xcd therefore anc is C
- 10 years agoHelpfull: Yes(3) No(0)
- Question is wrong. Actual Question is
ABCD is a rectangle , P & Q are the two points on AD & BC respectively.
x is another point on AB .
Now what is the ratio of ar(PQCD)/ar(xcd)...???
i) P is mid point on AD & Q is mid point on BC
ii) AB= 4 * XB
Ans:- a - 10 years agoHelpfull: Yes(0) No(0)
- Area of rectangle formed by PQCB is PQ*CQ
Area of triangle formed by XCB is (1/2)BC*AB
Here PQ=BC=AD; XN=AB=CD;
so the ratio PQCB:XCB=1:1 - 10 years agoHelpfull: Yes(0) No(0)
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