1024*128+256*512+10..Find occurance of two digit where base is 4

• 2^10*2^7+2^8*2^9+2^3+2
  2*2^16+2*2^16+2^3+2
  2^18+2^3+2
  4^9+2*4^1+2
  so number of two digits=2
• 10 years agoHelpfull: Yes(4) No(0)
• 2
• 10 years agoHelpfull: Yes(2) No(0)
• this ques is right aur question is different
• 10 years agoHelpfull: Yes(2) No(0)
• Ans is 2.
  1024*128+256*512+10
  =131072+131072+10
  =262154
  Now convert it to base 4
  =10 0000 0022 (number of two is 2 here)
• 10 years agoHelpfull: Yes(1) No(0)