Jake left point A for point B. 2hours and 15 minutes later,Paul left A for B and arrived at B at the same time as Jake. Had both of them started simultaneously from A and B travelling towards each other, they would have met in 120 minutes.How much tlme (hours) did it take for the slower one to travel from A to B if the ratio of speeds of the faster to slower is 3:1?

• Take Jake speed = j and Paul = p kmph.
  Now given that Dj−Dp = 2 hr 15 min = 214 hrs = 9/4 hrs
  Also both of them together covered D distance in 2 hours. So Dj+Dp=2
  Adding these two equations will give us 2Dj=94+2=174 = 4 hours 15 minutes.
• 6 years agoHelpfull: Yes(3) No(5)
• 160..minutes
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