A number 10,10,101 when multiplied with N gives product P, such that N is any no with only 1 as its digit (eg. N = 11,111,1111,.......) .How many different digit can be possible in the product P.

(a) 2
(b) 3
(c) 4
(D) not remembered

• N*10*10*101=P
  P=N*100*(100+1)
  P=10000*N+100*N
  suppose if N=11 then P=111100
  if N=111 then P=1121100
  if N=1111 then P=11221100
  and N=11111 then P=112221100
  an so P only contains digits such as 0,1,2 with repeatations
  so answer is 3 (option b)
• 9 years agoHelpfull: Yes(72) No(10)
• ans is 4...coz after multiplying it many times there will come an ans having 4 different digits(1,2,3,4) and when u multiply it again with N having one more 1,then there will be repetation of the digits.
• 9 years agoHelpfull: Yes(18) No(12)
• N*10*10*101=P
  P=N*100*(100+1)
  P=10000*N+100*N
  suppose if N=11 then P=111100
  if N=111 then P=1121100
  if N=1111 then P=11221100
  an so P only contains digits such as 0,1,2 with repeatations
  so answer is 3
• 9 years agoHelpfull: Yes(10) No(3)
• answer will be 9
• 9 years agoHelpfull: Yes(9) No(7)
• if number is 1010101 then ans is 4(1,2,3,4)
  if number is 10,10,101 then ans is 3(0,1,2)
• 9 years agoHelpfull: Yes(6) No(0)
• answer will be 4... 0,1,2,3...if u are in doubt...just multiply it with 11111 and see for yourself if u get 3 or not
• 9 years agoHelpfull: Yes(2) No(1)
• answer will be 3 and digits are 1,2,3.
• 9 years agoHelpfull: Yes(1) No(3)
• vijay could you please explain how it would be 9?
• 9 years agoHelpfull: Yes(1) No(1)
• take N= 11111111111
  
• 9 years agoHelpfull: Yes(1) No(2)
• @Ram gud one bro .. 0,1,2 is correct
• 9 years agoHelpfull: Yes(1) No(1)
• ans is 4 bcoz o multiplying with largest possible 1111111 we got com of 4 digits
• 9 years agoHelpfull: Yes(1) No(0)
• ans will be 2 because u can multipli with N to any no among the three u will always get either 1 or 2 differnt digit
  ex:- 111111111*101=22222222211
• 9 years agoHelpfull: Yes(0) No(2)
• 2 diff no....i.e 0,1
• 9 years agoHelpfull: Yes(0) No(2)
• hh explain
• 9 years agoHelpfull: Yes(0) No(0)
• @rajat only 0,1,2 are repeated so how the answer is 4 instead of 3 pls explain.
• 9 years agoHelpfull: Yes(0) No(1)
• at most 3...start multiplying 1010101 with 1 as unit digit, then 11, 111 you will see the pattern that atmost 3 different digits are possible in P
• 9 years agoHelpfull: Yes(0) No(0)
• N*10*10*101=P
  P=N*100*(100+1)
  P=10000*N+100*N
  suppose if N=11 then P=111100
  if N=111 then P=1121100
  if N=1111 then P=11221100
  an so P only contains digits such as 0,1,2 with repeatations
  so answer is 3
  Read more at http://www.m4maths.com/placement-puzzles.php?ISSOLVED=&page=2&LPP=10&SOURCE=Elitmus&MYPUZZLE=&UID=&TOPIC=Numerical%20Ability&SUB_TOPIC=Number%20System#hFd5u7T02MPjt111.99
• 9 years agoHelpfull: Yes(0) No(1)
• 10 digits are possible 0 to 9.
  Furthermore, the multiplication gives a pallindrome.
• 9 years agoHelpfull: Yes(0) No(1)
• 10 digits are possible 0 to 9.
  
• 9 years agoHelpfull: Yes(0) No(1)
• 3 becoz digits are (0,1,2)
• 7 years agoHelpfull: Yes(0) No(0)