if L1 and L2 are length of two train.
If they are moving with speed of V1&V2 km/hr respectivly in opposit direction they met at t sec.If they are moving in same direction the faster train cross slower train in T sec.If the ratio T/t=11sec.What is the ratio of V1 &V2.

• for trains moving in opp direction
  t=(L1+L2)/(V1+V2)
  for trains moving in same direction
  T=(L1+L2)/(V1-V2)
  by dividing the eq
  V1/V2=6/5.
• 9 years agoHelpfull: Yes(28) No(0)
• There is small mistake in question the ques should be "in opposite direction they cross each other (instead of met) at t sec"
  then
  6/5 is the ans considering v1 > v2
• 9 years agoHelpfull: Yes(3) No(0)
• v1/v2=5/6 or 6/5
• 9 years agoHelpfull: Yes(1) No(6)
• question needs to be modified i think
  they cross each other in t seconds while travelling in opposite direction
  then,
  t=(l1+l2)/(v1+v2)
  T=(l1+l2)/(v1-v2)
  eq2/eq1
  v1/v2=6/5
• 9 years agoHelpfull: Yes(1) No(0)
• Ans-6/5
  in opposite direction speed adds up
  in opposite direction speed minus
  
• 8 years agoHelpfull: Yes(0) No(0)