A boy cycles x km at10 km/hr and a further (x+4) km at 8 km/hr. If the total time taken is 5 hours, then x is.?

• ans is 20
  x/10 + (x+4/8) = 5
  8x + 10× + 40= 400
  18x = 360
  x = 20
• 10 years agoHelpfull: Yes(19) No(0)
• Speed = Distance/ time taken
  thus from given x/t =10 and (x+4)/t1 =8 and t+t1 =5
  now substitute t as 5-t1,
  hence x/(5-t1) =10 and it becomes 50-10t1 = x
  now substitute x in 2nd given equation,
  (50-10t1+4)/t1 =8
  54-10t1 =8t1
  18t1 =54
  thus t1 =3
  substitute t1 in 50-10t1 =x
  thus x = 50-3(10)
  x=20
  hence x is 20
• 10 years agoHelpfull: Yes(4) No(0)
• ANS IS 20 KM
  x/10+ x+4/8=5
  8x+10x+40= 5*80
  18x=360
  x=20
• 10 years agoHelpfull: Yes(3) No(0)
• (x/10)+(x+4/8)=5
  x=20 km
• 10 years agoHelpfull: Yes(3) No(0)
• x/10+(x+4)/8=5 i.e. total time taken , found = given
  4x+5x+20=200
  9x=180
  x=20km
  
  ans. 20km
• 10 years agoHelpfull: Yes(2) No(0)
• ans is 45km
  (x/10+4/8)=5
  8x=400-40
  x=45km
• 10 years agoHelpfull: Yes(1) No(4)
• x/10+(x+4)/8=5
  (4x+5x+20)=200
  9x=200-20
  9x=180
  x=20 km
• 10 years agoHelpfull: Yes(1) No(0)
• 20 km
  coz let 5=x/10 +x+4/8
• 10 years agoHelpfull: Yes(1) No(0)
• x/10+(x+4)/8=5
  8x+10x+40=400
  18x=360
  x=20
• 10 years agoHelpfull: Yes(1) No(0)
• t1 + t2 = 5hours -(1) (total time for both journeys)
  Here, t1= x / 10 (using formula time = distance/speed)
  Similarly t2= (x+4) / 8
  put these in equation (1) and solve,.
  we will get x= 20 km/hr
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• pls i need correct answer
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• ans is 20
  x/10+(x+4)/8=5
  x=20
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• x=20 km
  total time taken= 5 hrs
  x/10+ (x+4)/8=5
  4x+5x+20=200
  9x=180
  x=20
• 10 years agoHelpfull: Yes(0) No(0)
• (x/10)+((x+4)/8)=5
  x=20
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• (x+4/8)+(x/10)=5
  then x=20
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• ans.x=20
  exp x/10+(x+4)/8=5
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• 20km
  x/10+x+4/8=5
  solving this we get x=20
  
• 10 years agoHelpfull: Yes(0) No(0)
• x/10+(x+4)/8=5 i.e. total time taken , found = given
  4x+5x+20=200
  9x=180
  x=20km
  
  ans. 20km
  
• 10 years agoHelpfull: Yes(0) No(1)
• ans : x=20km
• 9 years agoHelpfull: Yes(0) No(0)