the price of a commodity(in rupees per kilogram) is 100+0.1n, on the nthvday of 2007(n=1,2,,,,,100), and then remains constant. On the other hand, the price of another commodity is 89+0.15n on the nth day of 2007(n=1,2,,,,,,365). On which date in 2007, will the price of these twocommodities be equal????




ans:- may 20

• price of both the commodity cannot be same within 100days( by puttng n=100 in both the price)
  price of 1st commodity after 100 days =100+0.1*100= 110
  day on which 2nd commodity becomes equal to 1st= 89+0.15n=110
  n=140
  140th day of 2007 is 20th may ANS
• 10 years agoHelpfull: Yes(16) No(0)
• Price of commodity 1 -(100+0.1n)
  Here n range is from (1-100)
  Also Price of commodity 2- (89+0.15n)
  lets check for n==100
  if commodity 2 price> commodity 1
  then n100
  commodity1(n=100) = 110
  commodity2(n-100) = 104
  
  Hence price of these 2 commodities will be equal after n=100
  Therefore price of commodity 1 will be constant at 100
  
  hence just solve commodity 2 equation by equating to price of commodity 1 at n=100 i.e 110
  89+0.15n=110
  n=21/0.15
  140.
  
  Now Jan=31, Feb=28 , Mar=31 , Apr=30, May=20
  31+28+31+30+20 = 140
• 10 years agoHelpfull: Yes(8) No(0)
• simple its 20
• 10 years agoHelpfull: Yes(0) No(0)