In this question A B means A raised to the power B Let f X 1 X X 2 X

ans is 0.

f(X^0)=x^0+x^1....+x^6
f(x^7)=x^7+x^8....+x^13

put x=1,remainder is 0.
9 years agoHelpfull: Yes(2) No(9)
answer is zero take x=0,1 and -1
9 years agoHelpfull: Yes(1) No(0)
can any one tell me f(x)=1+x+x^2...x^n=?.....it is an eq...it can be easily solve
9 years agoHelpfull: Yes(0) No(2)
No Option
9 years agoHelpfull: Yes(0) No(0)
for x=2 f(2^7)=f(128)=1+128+(128)^2+...(128)^6=4.432676799*10^12
f(2)=1+2+4+8+16+32+64=127
remainder for f(2^7)/f(2) is 0
9 years agoHelpfull: Yes(0) No(0)
Ravi can u explain the solution of this
9 years agoHelpfull: Yes(0) No(0)
plzzz give me the correct answer..
9 years agoHelpfull: Yes(0) No(0)
x^7=1+x^7+x^14----+X^42 (replace x in F(x) by x^7)

if x=1, then f(x^7)= 42

now, if x=1, then f(x)= 6,

so answer =0
9 years agoHelpfull: Yes(0) No(0)

In this question A^B means A raised to the power B. Let f(X)=1+X+X^2+.....X^6.
The reamainder when f(X^7) is divided by f(X) is:
1. 7
2. 0
3. 6