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Exam
Numerical Ability
Arithmetic
Find the number of trailing zeros in 972436851!
Read Solution (Total 2)
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- [972436851/5^1] + [972436851/5^2] + [972436851/5^3] + [972436851/5^4] + [972436851/5^5] + [972436851/5^6] + [972436851/5^7] + [972436851/5^8] + [972436851/5^9] + [972436851/5^10] + [972436851/5^11] + [972436851/5^12] = 243109204
so the number of trailing zeros in 972436851! = 243109204 - 9 years agoHelpfull: Yes(2) No(1)
- [972436851/5] + [194487370/5] + [38897474/5] + [7779494/5] + [1555898/5] + [311179/5] + [62235/5] + [12447/5] + [2489/5] + [497/5] + [99/5] + [19/5] = 243109204
OR
[972436851/5^1] + [972436851/5^2] + [972436851/5^3] + [972436851/5^4] + [972436851/5^5] + [972436851/5^6] + [972436851/5^7] + [972436851/5^8] + [972436851/5^9] + [972436851/5^10] + [972436851/5^11] + [972436851/5^12] = 243109204
Both the solution is same
- 9 years agoHelpfull: Yes(1) No(0)
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