find the average of 40 natural numbers that come first

• natural number:The whole numbers from 1 upwards: 1, 2, 3, and so on ...
  hence we know,sum of n natural number=n(n+1)/2
  =40*41/2
  =820
  avg=820/40=20.5
• 10 years agoHelpfull: Yes(16) No(1)
• (1+2+3+----+40)/40
  =40*41/(2*40)[sum of n natural no.s= n*(n+1)/2]
  =41/2
  =20.5
• 10 years agoHelpfull: Yes(5) No(1)
• answer is 20.5
  sum of 1 to 40 natural number will be n/2(a+l)
  40/2(1+40)=820
  so average=820 /40 =20.5
  
• 10 years agoHelpfull: Yes(4) No(1)
• Is this really a elitmus question?
• 10 years agoHelpfull: Yes(2) No(3)
• This question not elitmus level
  but Ans: 20.5
  1 to 40 sum
  so the numbers in A . P.
  according formula : (first term + last term)/2
  (1+40)/2 = 20.5
• 7 years agoHelpfull: Yes(1) No(0)
• n(n+1)/2 = sum first n natural numbers
  
• 9 years agoHelpfull: Yes(0) No(0)
• ans) 20.5
  natural numbers are 1,2,3,4.......................40.
  so, sum of 40 natural numbers are n(n+1)/2
  according to formula, sum = 40(41)/2
  avg = sum/total no.
  so, (40(41)/2)/40= 41/2 = 20.5
• 9 years agoHelpfull: Yes(0) No(0)
• Ans is 20.5
  Average of first 'n' natural no. = n+1/2
  (Additional information :p)
  Average of first 'n' even no. = n+1
• 7 years agoHelpfull: Yes(0) No(0)