odds in favour of a is 5/3.and evens in against for event b is 4/5.then what is probabelity of occuring at least one event.

• Answer is 0.792
  odds in favor=a/1-a =5/3
  probability of occurring of a event=a= 5/8
  evens in against b=odds in favor of b=b/(1-b)=4/5
  probability of occurring of b event=b=4/9
  probability of occurring at least one event
  =5/8+4/9-(5/8)*(4/9)
  =0.625+0.445-0.278
  =0.792
• 9 years agoHelpfull: Yes(1) No(0)