3x+2y=100.
find the maximum possible solutions,

• Infinite solutions are possible since there are no conditions on x and y
  Assuming x and y to be positive,
  
  3x+2y=100
  => x = (100 - 2y)/3
  
  (100 - 2y) is divisible by 3 only if y = 2,5,8,11 ... 47
  
  i.e. 16 solutions possible.
• 10 years agoHelpfull: Yes(2) No(0)