A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 25%. The percentage of water in the mixture is:

A.4%
B.6%
C.20%
D.25%

• Let C.P Of 1 Litre Milk Be Rs.1
  Then,S.P Of 1 Litre=1 Gain=25%
  C.p of 1 Litre Mixture=Re.(100/125*1)=Re.4/5
  Ratio of milk in water=4/5:1/5
  Percetage Of Water In mixture=(1/5*100)%=20%
  Ans:c
• 10 years agoHelpfull: Yes(10) No(2)
• Ans)D (25%)
  because gain % is equal to the water % in the mixture
  so the percentage of water in the mixture is 25%....
• 11 years agoHelpfull: Yes(2) No(29)
• let x lit of milk costs Rs x(i.e. Rs 1/lit)
  hence, c.p=Rs x
  let y lit of water added
  hence, s.p=x+y
  SP = ((100 + Gain %)/100) x C.P
  substituting in above x/x+y =1/1.25
  now y/x+y =1-(x/x+y)=0.2
  hence,The percentage of water in the mixture is 20%
• 7 years agoHelpfull: Yes(1) No(0)
• ANS : C
  profit is 25%.
  profit/CP=25%
  (SP-CP)/CP=25/100
  (SP-CP)*100=25CP
  Let the selling price be 100 rs/litre.
  (100-CP)*100=25CP
  10000-100CP=25CP
  10000=125CP
  CP=10000/25=80 rs.
  Equivalent milk for rs 80 = 800 ml
  Water added = 200 ml
  Therefore water % = 20%
• 7 years agoHelpfull: Yes(1) No(0)