i rope is cut into 4 part and one part is of 3cm , then what is the size of smallest part
a) sum of first three part =11cm
b) sum of last three part =10 cm

• sorry 1 thing i forgot to mention that size of each part will be different
  
  @ Erfan jawed bro ? about 7+3+1+6
  
  I think ans should be both are insufficient
  because we have many soln like 7+3+1+6 , 4+5+2+3 so we cant say about smallest part using two statement or alone ,because we have multiple soln like 1 ,2 etc
• 10 years agoHelpfull: Yes(33) No(2)
• 3 7 1 2, so smallest is 1
  
• 10 years agoHelpfull: Yes(5) No(6)
• both a and b are insufficient to ans.
  3264 gives 2 as a smallest number
  3628 gives 2 as a smallest number
  but
  3719 gives 1 as a smallest number....so we cant find the smallest number by using both...
  ans is both are insufficient tpo answer..
• 10 years agoHelpfull: Yes(5) No(3)
• even both statement together are not sufficient to answer. bcoz solution is not unique we can get many solutions.
  
• 10 years agoHelpfull: Yes(3) No(1)
• Both the stmnts are insufficient 2 ans......bcoz of many solns
  like 2,3,6,1 or 4,5,2,3 or many more.
• 9 years agoHelpfull: Yes(2) No(0)
• There will be two solutions, 4,1,6,3 4,2,5,3
  so data is insufficient
  
• 9 years agoHelpfull: Yes(2) No(0)
• 4+5+2+3
  ans:2
• 10 years agoHelpfull: Yes(1) No(6)
• first part= 6
  second part = 3
  third part= 2
  fourth = 5
  hence both the conditions are required....
• 10 years agoHelpfull: Yes(1) No(3)
• Both the statements are compulsory..
  Suppose a, b, c & d r 4 parts of rope of diff lnth.
  a =3
  Given in question,
  a+b+c=11,
  b+c+d=10
  If we subtract both eqations we will get ans
  Smallest part as 2
• 9 years agoHelpfull: Yes(1) No(0)
• Both answer
  
• 10 years agoHelpfull: Yes(0) No(2)
• Both are required...
  
• 10 years agoHelpfull: Yes(0) No(0)
• first part= 6
  second part = 3
  third part= 2
  fourth = 5
• 10 years agoHelpfull: Yes(0) No(0)
• 1st part=2, sec prt=3, thrd prt=6, frth prt=1
• 10 years agoHelpfull: Yes(0) No(1)
• first part=3, second part =4, third part=4, Fourth part=2
  sum of first three part is=3+4+4=11
  sum of last three part is=4+4+2=10
  smallest part=2
• 10 years agoHelpfull: Yes(0) No(2)
• Solutions of set 1 are : 2,3,6 ; 1,2,8 ; 1,3,7 ; 2,3,5
  set 2 are : 1,2,7 ; 1,3,6 ; 1,4,5 ; 2,3,5
  moreover from set 1 and set 2 there are two possible solutions i.e. First : 2,3,6 (first three ) and 1,4,5 (last three) Second : 1,4,6 (first three ) and 2,3,5 (last three) and in both ans minimum value is 1 . Hence, ans is a .
• 9 years agoHelpfull: Yes(0) No(0)
• it is already mentioned in question that the smallest part so
  4+1+6+3
  the smallest part must be 1 cm
  
• 9 years agoHelpfull: Yes(0) No(0)