Three dice are rolled. What is the probability of getting the sum as 13?

• possibilities are
  (1,6,6) -> 3!/2! = 3, as the same numbers can occur in different dices
  (2,5,6) -> 3! = 6
  (3,5,5) -> 3!/2! = 3
  (3,4,6) -> 3! = 6
  (4,4,5) -> 3!/2! = 3
  
  total possibility = 3+6+3+6+3 = 21
  total chances = 6^3 = 216
  probability = 21/216 = 7/72 answer
• 9 years agoHelpfull: Yes(62) No(5)
• It is all u have to mug up the sequence of suming 3 dies:
  to get sum of 3=1
  4=3
  5=6
  6=10
  7=15
  8=21
  9=25
  10-27
  similarly write the sequence in reverse order now,
  11=27
  12=25
  13=21
  14=15
  15=10
  16=6
  17=3
  18=1
  so if u remember this then,few seconds enough to answer the prob of sum of 13
  21/216
• 9 years agoHelpfull: Yes(2) No(0)
• 1/12 ass 6,6,1;5,6,2;4,6,3;3,6,4;2,6,5;1,6,6 for 1 dice.
  like wise for other 2 dice.total is 6^3=216.
  so 18/216 is 1/12.
• 9 years agoHelpfull: Yes(1) No(2)
• ans is 21/216
• 9 years agoHelpfull: Yes(1) No(0)
• If the numbers of 2 dice are decided then only one number is possible on the third dieIf the value on the first die is 1 then the value on the 2nd die must be 6 then there is 1 possibility similarly if the value on 1st die is 2 then the value on 2nd die must be 5 or 6 similarly for all other combinationsTotal number of outcomes1345215Therefore probability15216total chances63
• 9 years agoHelpfull: Yes(1) No(0)
• bhaskar is right 21/216
• 9 years agoHelpfull: Yes(1) No(0)
• 21/216=7/72(ANS)
• 9 years agoHelpfull: Yes(1) No(0)
• the answr myt b 4
• 9 years agoHelpfull: Yes(0) No(0)
• 15
  1,6,6 ----in 3 ways
  2,5,6----- in 6 ways
  3,4,6------in 6 ways
• 9 years agoHelpfull: Yes(0) No(0)
• 2721618
• 9 years agoHelpfull: Yes(0) No(0)
• possibilities are:
  (6,6,1)
  (6,5,2)
  (6,4,3)
  (6,3,4)
  (6,2,5)
  (6,1,6)
  (5,6,2)
  (5,5,3)
  (5,4,4)
  (5,3,5)
  (5,2,6)
  (4,6,3)
  (4,5,4)
  (4,4,5)
  (4,3,6)
  (3,6,4)
  (3,5,5)
  (3,4,6)
  (2,6,4)
  (2,4,6)
  (1,6,6)
  
  So if the sum starts with "6" we get 6 possibilities, similarly we 5 possibilities if started with 5, 4 with 4, 3 with 3, 2 with 2, 1 with 1.
  sum of the possibilities is 6+5+4+3+2+1=21
  total chances= 6^3 = 216
  total possibilities= 21/216
• 7 years agoHelpfull: Yes(0) No(0)