Q. Two dice are tossed. The probability that the total score is a prime number is:

Option
A. 1/6
B. 5/12
C. 1/2
D. 7/9

• first hav to write prime numbers below 12 because 6,6 sum ends with 12,so there ll be 15 terms as like 1 1,2 1,1 2,.........6 5,so 15/36=5/12
• 12 years agoHelpfull: Yes(11) No(3)
• In Simultaneous Throw Of Two Dice,n(S)=6*6=36
  let E=Event Of Getting A Prime Number={(1,1),(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)}
  P(E)=n(E)/n(S)
  =12/36
  =5/12
• 11 years agoHelpfull: Yes(6) No(0)
• 2has1poss
  3has2;
  5has4;
  7has6
  11as2
  total 15 poss so 15/36=5/12
  
• 12 years agoHelpfull: Yes(3) No(2)
• two dice are solved then we get probality pf dice=6*6=36
  prime probability=((2,1),(2,3),(1,2),(1,4),(3,2),(1,6),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5),(1,1),(2,5))=15
  nowtotal score is=prime probabilty/probability of 2 dice=15/36
• 10 years agoHelpfull: Yes(3) No(1)
• total events= 36
  favourable events= 11, 12, 14, 16, 21, 23, 25, 32, 34, 41, 43, 52, 56, 61, 65
  probability = 15/36 = 5/12
• 8 years agoHelpfull: Yes(0) No(0)