There is a bacteria which has the probability of die 13 of its total number or it may tripled Find out the probabilityA P1323p3 B P2323p3 C P2313p3 D P2323p3

• Original question is like this
  
  There is a bacteria which has the probability of die 1/3 of its total number or it may tripled. Find out the probability
  A. P=1/3+(2/3*p^3)
  B. P=2/3+(2/3*p^3)
  C. P=2/3+(1/3*p^3)
  D P=2/3+(2/3*p^3)
  
  Answer : 1/3+(2/3*p^3)
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• let p be the probabilityprobability of die13probability of alive23if alive it gets tripled23p3total probability1323p3option A is true
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• FROM WHERE U( ANUJ ) GET ORIGINAL QUESTION
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• probability of die is 1/3
  
  or
  its get tripled
  the probability of tripled is 2/3*p*p*p
  thats 2/3*p^3
  
  so both the probability combined as P=1/3+(2/3*p^3)
• 9 years agoHelpfull: Yes(0) No(0)