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There is a bacteria which has the probability of die 13 of its total number or it may tripled Find out the probabilityA P1323p3 B P2323p3 C P2313p3 D P2323p3
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- Original question is like this
There is a bacteria which has the probability of die 1/3 of its total number or it may tripled. Find out the probability
A. P=1/3+(2/3*p^3)
B. P=2/3+(2/3*p^3)
C. P=2/3+(1/3*p^3)
D P=2/3+(2/3*p^3)
Answer : 1/3+(2/3*p^3) - 10 years agoHelpfull: Yes(15) No(0)
- let p be the probabilityprobability of die13probability of alive23if alive it gets tripled23p3total probability1323p3option A is true
- 10 years agoHelpfull: Yes(2) No(0)
- FROM WHERE U( ANUJ ) GET ORIGINAL QUESTION
- 10 years agoHelpfull: Yes(0) No(1)
- probability of die is 1/3
or
its get tripled
the probability of tripled is 2/3*p*p*p
thats 2/3*p^3
so both the probability combined as P=1/3+(2/3*p^3) - 8 years agoHelpfull: Yes(0) No(0)
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