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Maths Puzzle
Numerical Ability
Sequence and Series
If 2=9
3=29
4=67
5=129
than 6=?
Read Solution (Total 4)
-
- 2^3+1 = 8+1 = 9
3^3+2 = 27+2 = 29
4^3+3 = 64+9 = 67
5^3+4 = 125+4 = 129
6^3+5 = 216+5 = 221
221 is the answer - 10 years agoHelpfull: Yes(3) No(0)
- 2=2^3+(2-1)= 9
3=3^3+(3-1)= 29
4=4^3+(4-1)= 67
5=5^3+(5-1)= 129
6=6^3+(6-1)= 221
and so on......
so Answer is 221 - 10 years agoHelpfull: Yes(1) No(0)
- using qube and add formula
221 - 10 years agoHelpfull: Yes(0) No(0)
- 2^3+1 = 8+1 = 9
3^3+2 = 27+2 = 29
4^3+3 = 64+9 = 67
5^3+4 = 125+4 = 129
6^3+5 = 216+5 = 221
221 will be answer - 10 years agoHelpfull: Yes(0) No(0)
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