Given digits 2,2,3,3,3,4,4,4,4, how many distinct 4 digit numbers greater than 3000 can be formed?
a) 50 b) 51 c) 52 d) 54

• 3_ _ _
  (2,3,4)--3! ways distinctly
  (2,2,3),(2,2,4),(3,3,2),(3,3,4),(4,4,2),(4,4,3)--(3!/2!)*6 ways
  (4,4,4)--1 way
  so distinct 4 digit numbers starting with 3=6+18+1=25
  4_ _ _
  (2,3,4)--3! ways distinctly
  (2,2,3),(2,2,4),(3,3,2),(3,3,4),(4,4,2),(4,4,3)--(3!/2!)*6 ways
  (3,3,3),(4,4,4)--2 ways
  so distinct 4 digit numbers starting with 3=6+18+2=26
  so Numbers >3000=25+26=51 (option b)
  
• 9 years agoHelpfull: Yes(2) No(5)