find remainder of 7^5^5^5/11

• first compute the unit digit of 5^5^5 i.e. 5
  so Rem[7^5]/11= Rem[(7^2)^2*7]/11=Rem[(49)^2*7]/11=Rem[5^2 *7]/11=Rem[25 * 7]/11
  =Rem[3*7]/11=Rem[21]/11=10
• 10 years agoHelpfull: Yes(15) No(2)
• sorry ...the above is wrong ans is 10
  (7^5^5^5)/11=7^5/11=10
• 10 years agoHelpfull: Yes(4) No(1)
• First find the remainder of 5^5^5 is 5
  7^5/11=7
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• ans is 7...........
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• yar plz ache se explain krdo 10 kaise aya..... vese to 7 anna chaiyen
  
• 10 years agoHelpfull: Yes(1) No(2)
• answer is 10
  
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• 7x5x5x5/11=7x125/11=875/11=rem=6
• 10 years agoHelpfull: Yes(0) No(6)
• Answer is 7
  8
• 10 years agoHelpfull: Yes(0) No(1)