Accenture
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Numerical Ability
Quadratic Equations
Two circles touch each other externally. The distance between their centres is 14 cm and the sum of their areas is 130 cm2. Find their radii.
Read Solution (Total 9)
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- sum of area = 130pi
let radius of circles are x,14-x.
so, pi*x^2+pi*(!4-x)^2=130pi
x^2-14x+33=0
(x-3)(x-11)=0
by solving this we wil get x=3,11
so their radii are 3,11. - 10 years agoHelpfull: Yes(8) No(1)
- let the radius of 1st circle be xcm.
and the radius of 2nd one is (14-x)cm.
so,
(pi*x*x)+(pi*(14-x)*(14-x))=130
from here we can find the value of x. - 10 years agoHelpfull: Yes(4) No(1)
- @ krishna mahato how u are solving by taking the area as 130pi wen d area is 130 cm^2
- 10 years agoHelpfull: Yes(3) No(0)
- Question wrong....
two circles touch externally the sum of their areas is 130pi cm2 and the distance between their centres is 14cm find the sum of their radii - 10 years agoHelpfull: Yes(1) No(3)
- let d radius of 1 circle = x
other one = 14-x
now apply the formula and put the value get the ans - 10 years agoHelpfull: Yes(1) No(0)
- radius of each circle is 7 cm. as both of the circles touches each other externally so the distance of their centres will act sa diameter and thus radii will be 7 cm.
- 10 years agoHelpfull: Yes(0) No(2)
- wrong question
as R^2 + r^2 = 130/pi = (130/22)*7 = 41.37 ...................i
and R + r = 14...................................................................ii
how i and ii are possible while
1^2 + 11^2 = 122
2^2 + 10^2 = 104
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7^2 + 7^2 = 96
- 10 years agoHelpfull: Yes(0) No(0)
- let it go.. :p
- 10 years agoHelpfull: Yes(0) No(1)
- ans: 7.664 cm and 6.336 cm
- 9 years agoHelpfull: Yes(0) No(0)
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