1,11,21,1211,111231,?
a.31121311
b.11231332
c.23423344
d.23214244

• The correct question is:
  1, 11, 21, 1211, 111221, 312211, ______
  
  each term is the description of the previous term.
  see the second term it describes first term in numeric language:
  one 1 = 11
  now in 11 there are:
  two 1= 21
  now in 21 there are:
  one 2 & one 1 = 1211
  now in 1211 there are:
  one 1 one 2 & two 1 = 111221
  now in 111221 there are:
  three 1 two 2 and one 1 = 312211
  
  So the correct answer is 312211.
  provided options are not correct.
  and series goes like this:
  
  1, 11, 21, 1211, 111221, 312211, 13112221..... and so on
• 9 years agoHelpfull: Yes(90) No(2)
• a
  last digit is always 1
• 9 years agoHelpfull: Yes(8) No(2)
• 1 One
  11 One One
  21 Two One(s)
  1211 One Two and One One(s)
  111221 One One, One Two, and Two One(s)
  I propose the next line to be a description of 111221:
  312211 Three One(s), Two Two(s), and One One
• 9 years agoHelpfull: Yes(2) No(0)
• 111231 is worng it should be 111221
  Then ans is : 31121211
  read off the digits of the previous member, counting the number of digits in groups of the same digit
• 9 years agoHelpfull: Yes(1) No(0)
• 1.
  1 is at the end of all number.
• 9 years agoHelpfull: Yes(1) No(2)
• send me too at kundukrishanu01@gmail.com
• 9 years agoHelpfull: Yes(1) No(0)
• option a becoz from digit one we have one ones and from 11 we have 2 ones is 21 like sooo on ,,,,,, from 111231 we have 31121311
• 9 years agoHelpfull: Yes(1) No(0)
• last digit is one so option a is correct
• 8 years agoHelpfull: Yes(0) No(0)
• a
  one ,one one's and 21-two 1's and so on.........
• 8 years agoHelpfull: Yes(0) No(0)
• a.31121311
• 8 years agoHelpfull: Yes(0) No(0)
• obviously , ans. is (a) because last digit is 1
  
• 8 years agoHelpfull: Yes(0) No(0)
• (A)31121311
• 8 years agoHelpfull: Yes(0) No(0)
• Can anybody plz snd me tech mahindra previous papers.......kindly plzzzzzz on
  nikital13m@gmail.com
• 5 years agoHelpfull: Yes(0) No(0)