2. Suppose that n married couples arrive at a party and everyone shakes hands with everyone else, except
of course that there are no handshakes between spouses. How many handshakes are there in all?

• 2n(2n-2) e.g if n=4 i.e 4 couple, thn 8 person. A single person handshak with 6 people.. then 8 people 6*8.
• 9 years agoHelpfull: Yes(12) No(5)
• Ans is 2n(n-1)....
  If 2 couples
  then n=2 no. Of handshakes 4.
  
  If three couples then handshakes are 12.
• 9 years agoHelpfull: Yes(8) No(2)
• ANS: summation 1 to N of 4(N-1)
  For 1 couple,handshakes=0
  For 2 couples,handshakes=4
  For 3 couples,handshakes=12
  For 4 couples,handshakes=24
  For 5 couples,handshake=40
  
  So this follows a pattern and that is summation 1 to n of 4(n-1)
• 9 years agoHelpfull: Yes(2) No(2)
• Answer :2*n(n-1)
  
  Where n is a number of couple
  100 % correct answer
• 8 years agoHelpfull: Yes(2) No(0)
• Answer :2*n(n-1)
  
  Where n is a number of couple
  100 % correct answer
• 8 years agoHelpfull: Yes(1) No(0)
• 2n-2/2-n
  .............................................
  
• 9 years agoHelpfull: Yes(0) No(1)
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• 9 years agoHelpfull: Yes(0) No(0)
• n(n-1)/2
  
  i.e n(n-1) whole divided by 2
• 9 years agoHelpfull: Yes(0) No(0)
• simply there are n married couples so
  2nC2-n since spouces cannot make handshakes with one another
• 8 years agoHelpfull: Yes(0) No(0)
• n(n/2 - 1) suppose n = 4 means 8 persons. 1 couple will shake hand with 6+6 ( 6 for man and 6 for woman of same couple)
• 8 years agoHelpfull: Yes(0) No(0)
• 2n(n-1), self explanatory i guess..
• 6 years agoHelpfull: Yes(0) No(0)