other Maths Puzzle Numerical Ability

Find the last digit of
1!+2!+3!+4!+...............100!

Read Solution (Total 3)

Answer is 3.

5! +6! .... = always unit digit o.

1!+2!+3!+4! = 33

so, 33 + *0 = *3

so the unit digit will be 3
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Ans: 3
1+2+6+4+0+0...... = 0+3 = 3
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from 5! every no. contain its unit digit as 0
so upto 4! sum of digit is=33
last digit 3+0=3
ans-3
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other Other Question

N is an even 3-digit number such that the last 3 digits of N^2 are N itself. What is the value of N? If we know that a positive integer is a multiple of 4, how many (distinct) possibilities are there for the last digit of the integer?