3) If F(X) = AF(X)4 + B(X)2 + X + 5 , F(– 3) = 2, then F(3) = ?

• f(-3)=af(-3)4+bf(-3)+(-3)+5
  2=a*2*4+b*2+2
  8a+4b=0
  f(3)=af(3)4+bf(3)2+3+5
  f(3)[1-4a-2b]=_8
  multiply by 2 both sides
  f(3)[2-(8a+4b)]=16
  f(3)=8
  
• 10 years agoHelpfull: Yes(23) No(1)
• since value of even function is always
  f(-n)=f(n)
  so value of fn(3) will be 8A+4B+2
• 10 years agoHelpfull: Yes(1) No(1)
• answer is 8
  81a+9b-3+5=2
  =>81a+9b+5=5
  now f(3)
  81a+9b+3+5=5+3=8
• 10 years agoHelpfull: Yes(1) No(0)
• F(-3)=AF(-3)4+B(X)2+-3+5 = (5+(-3))= 2
  5+X= 5+3 = 8
• 10 years agoHelpfull: Yes(1) No(0)
• 12*150/99=18.18181818
• 10 years agoHelpfull: Yes(0) No(0)
• 4608/6=768
• 10 years agoHelpfull: Yes(0) No(0)
• question is wrong.
  the correct is
  If F(X) = AF(X)4 + BF(X)2 + X + 5 , F(– 3) = 2, then F(3) = ?
  
• 10 years agoHelpfull: Yes(0) No(0)
• SIMPLE SOLUTION
  f(-3)=2
  f(-2)=3
  f(-1)=4
  f(0)=5
  f(1)=6
  f(2)=7
  f(3)=8
  I hope its helps
• 5 years agoHelpfull: Yes(0) No(0)