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What is the chance that a leap year selected at random contains 53 fridays?
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- normal year =365 days
leap year = 366 days
now there are 52 weeks i.e. 364 days+2 odd days
the 2 odd may have Friday over a week has 7 days
so probability = 2/7 - 9 years agoHelpfull: Yes(22) No(2)
- leap year=366 days
52 weaks=364 days
p=2/7(ie u can select 2 days from remaining 7 days because 53 fridays is there) - 9 years agoHelpfull: Yes(3) No(0)
- p=2/7 crct ans
- 9 years agoHelpfull: Yes(1) No(0)
- Leap year=366 days
Now there is 52 weeks in a year.
So 52 weeks=364 days
so there is two days left.
so either it is thrusday & friday or it is friday & saturday
So, ans is=2/7 - 9 years agoHelpfull: Yes(1) No(0)
- 1/7
the year can start on any day
all days have equal prob - 9 years agoHelpfull: Yes(0) No(9)
- 2/7 is the rgt ans
- 9 years agoHelpfull: Yes(0) No(0)
- leap year=366 days
so 366/7=52 sundays
r=2 days
p=2/7 - 9 years agoHelpfull: Yes(0) No(0)
- normal year =365 days
leap year = 366 days
now there are 52 weeks i.e. 364 days+2 odd days
the 2 odd may have Friday over a week has 7 days
so probability = 2/7
- 9 years agoHelpfull: Yes(0) No(0)
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